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4435054479413 is a prime number
BaseRepresentation
bin100000010001001110111…
…0110001100100000110101
3120200222122120110010120022
41000202131312030200311
51040130442421320123
613233234053214525
7635264533032425
oct100423566144065
916628576403508
104435054479413
11145a9946a5208
125b7662931445
132622baa2398c
1411492cd50485
157a5750e61c8
hex4089dd8c835

4435054479413 has 2 divisors, whose sum is σ = 4435054479414. Its totient is φ = 4435054479412.

The previous prime is 4435054479391. The next prime is 4435054479431. The reversal of 4435054479413 is 3149744505344.

Together with next prime (4435054479431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4341814024804 + 93240454609 = 2083702^2 + 305353^2 .

It is a cyclic number.

It is not a de Polignac number, because 4435054479413 - 28 = 4435054479157 is a prime.

It is a super-2 number, since 2×44350544794132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4435054479463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217527239706 + 2217527239707.

It is an arithmetic number, because the mean of its divisors is an integer number (2217527239707).

Almost surely, 24435054479413 is an apocalyptic number.

It is an amenable number.

4435054479413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4435054479413 is an equidigital number, since it uses as much as digits as its factorization.

4435054479413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14515200, while the sum is 53.

The spelling of 4435054479413 in words is "four trillion, four hundred thirty-five billion, fifty-four million, four hundred seventy-nine thousand, four hundred thirteen".