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4440111402581 is a prime number
BaseRepresentation
bin100000010011100101101…
…0000110100111001010101
3120201110200222221110000222
41000213023100310321111
51040221322004340311
613235431540444125
7635534046130601
oct100471320647125
916643628843028
104440111402581
11146204a151458
125b86343a9645
132629155c2bca
14114c8c7cc501
157a76e043adb
hex409cb434e55

4440111402581 has 2 divisors, whose sum is σ = 4440111402582. Its totient is φ = 4440111402580.

The previous prime is 4440111402469. The next prime is 4440111402647. The reversal of 4440111402581 is 1852041110444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4440060051025 + 51351556 = 2107145^2 + 7166^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4440111402581 is a prime.

It is a super-2 number, since 2×44401114025812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4440111407581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220055701290 + 2220055701291.

It is an arithmetic number, because the mean of its divisors is an integer number (2220055701291).

Almost surely, 24440111402581 is an apocalyptic number.

It is an amenable number.

4440111402581 is a deficient number, since it is larger than the sum of its proper divisors (1).

4440111402581 is an equidigital number, since it uses as much as digits as its factorization.

4440111402581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20480, while the sum is 35.

The spelling of 4440111402581 in words is "four trillion, four hundred forty billion, one hundred eleven million, four hundred two thousand, five hundred eighty-one".