Base | Representation |
---|---|
bin | 101001010110100100… |
… | …101110001111011001 |
3 | 11020121110110102111012 |
4 | 221112210232033121 |
5 | 1211413421440441 |
6 | 32221551543305 |
7 | 3131216651363 |
oct | 512644561731 |
9 | 136543412435 |
10 | 44402140121 |
11 | 1791593a079 |
12 | 873222ab35 |
13 | 42580b46c1 |
14 | 22130c1d33 |
15 | 124d1e49eb |
hex | a5692e3d9 |
44402140121 has 2 divisors, whose sum is σ = 44402140122. Its totient is φ = 44402140120.
The previous prime is 44402140099. The next prime is 44402140127. The reversal of 44402140121 is 12104120444.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37806913600 + 6595226521 = 194440^2 + 81211^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-44402140121 is a prime.
It is not a weakly prime, because it can be changed into another prime (44402140127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22201070060 + 22201070061.
It is an arithmetic number, because the mean of its divisors is an integer number (22201070061).
Almost surely, 244402140121 is an apocalyptic number.
It is an amenable number.
44402140121 is a deficient number, since it is larger than the sum of its proper divisors (1).
44402140121 is an equidigital number, since it uses as much as digits as its factorization.
44402140121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1024, while the sum is 23.
Adding to 44402140121 its reverse (12104120444), we get a palindrome (56506260565).
The spelling of 44402140121 in words is "forty-four billion, four hundred two million, one hundred forty thousand, one hundred twenty-one".
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