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4440233310041 is a prime number
BaseRepresentation
bin100000010011101001010…
…0001110111011101011001
3120201111000111022222122002
41000213102201313131121
51040222044211410131
613235452013410345
7635540056255124
oct100472241673531
916644014288562
104440233310041
111462101a46321
125b86691999b5
132629349370b9
14114ca0a833bb
157a779ac46cb
hex409d2877759

4440233310041 has 2 divisors, whose sum is σ = 4440233310042. Its totient is φ = 4440233310040.

The previous prime is 4440233310013. The next prime is 4440233310109. The reversal of 4440233310041 is 1400133320444.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2498836954441 + 1941396355600 = 1580771^2 + 1393340^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4440233310041 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4440233309986 and 4440233310013.

It is not a weakly prime, because it can be changed into another prime (4440233310341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220116655020 + 2220116655021.

It is an arithmetic number, because the mean of its divisors is an integer number (2220116655021).

Almost surely, 24440233310041 is an apocalyptic number.

It is an amenable number.

4440233310041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4440233310041 is an equidigital number, since it uses as much as digits as its factorization.

4440233310041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4440233310041 its reverse (1400133320444), we get a palindrome (5840366630485).

The spelling of 4440233310041 in words is "four trillion, four hundred forty billion, two hundred thirty-three million, three hundred ten thousand, forty-one".