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4440322113442 = 2592637794041
BaseRepresentation
bin100000010011101011111…
…0100100111111110100010
3120201111020200102122222221
41000213113310213332202
51040222234430112232
613235504505021254
7635542215135145
oct100472764477642
916644220378887
104440322113442
11146214808a666
125b8692a8482a
1326294a15a4a7
14114cac79c05c
157a7827b6897
hex409d7d27fa2

4440322113442 has 12 divisors (see below), whose sum is σ = 6775286108166. Its totient is φ = 2182531204880.

The previous prime is 4440322113421. The next prime is 4440322113509. The reversal of 4440322113442 is 2443112230444.

It can be written as a sum of positive squares in only one way, i.e., 4087962340641 + 352359772801 = 2021871^2 + 593599^2 .

It is a super-2 number, since 2×44403221134422 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4440322113398 and 4440322113407.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 318890059 + ... + 318903982.

Almost surely, 24440322113442 is an apocalyptic number.

4440322113442 is a deficient number, since it is larger than the sum of its proper divisors (2334963994724).

4440322113442 is an equidigital number, since it uses as much as digits as its factorization.

4440322113442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 637794161 (or 637794102 counting only the distinct ones).

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 4440322113442 its reverse (2443112230444), we get a palindrome (6883434343886).

The spelling of 4440322113442 in words is "four trillion, four hundred forty billion, three hundred twenty-two million, one hundred thirteen thousand, four hundred forty-two".

Divisors: 1 2 59 118 3481 6962 637794041 1275588082 37629848419 75259696838 2220161056721 4440322113442