Base | Representation |
---|---|
bin | 101001010111001100… |
… | …000011101011010101 |
3 | 11020122011212022002122 |
4 | 221113030003223111 |
5 | 1211424041422131 |
6 | 32223000545325 |
7 | 3131403416003 |
oct | 512714035325 |
9 | 136564768078 |
10 | 44412451541 |
11 | 17920742207 |
12 | 8735782245 |
13 | 425a284c33 |
14 | 2214607a73 |
15 | 124e07ed7b |
hex | a57303ad5 |
44412451541 has 2 divisors, whose sum is σ = 44412451542. Its totient is φ = 44412451540.
The previous prime is 44412451507. The next prime is 44412451547. The reversal of 44412451541 is 14515421444.
44412451541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28542750916 + 15869700625 = 168946^2 + 125975^2 .
It is a cyclic number.
It is not a de Polignac number, because 44412451541 - 230 = 43338709717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44412451547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22206225770 + 22206225771.
It is an arithmetic number, because the mean of its divisors is an integer number (22206225771).
Almost surely, 244412451541 is an apocalyptic number.
It is an amenable number.
44412451541 is a deficient number, since it is larger than the sum of its proper divisors (1).
44412451541 is an equidigital number, since it uses as much as digits as its factorization.
44412451541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51200, while the sum is 35.
Adding to 44412451541 its reverse (14515421444), we get a palindrome (58927872985).
The spelling of 44412451541 in words is "forty-four billion, four hundred twelve million, four hundred fifty-one thousand, five hundred forty-one".
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