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4442113037897 is a prime number
BaseRepresentation
bin100000010100100001010…
…0100011101011001001001
3120201122212111101001111022
41000221002210131121021
51040234421414203042
613240402322442225
7635634462553223
oct100510244353111
916648774331438
104442113037897
111462987005717
125b8ab2803375
13262b741c06c2
14114ddc591413
157a839b2acd2
hex40a4291d649

4442113037897 has 2 divisors, whose sum is σ = 4442113037898. Its totient is φ = 4442113037896.

The previous prime is 4442113037849. The next prime is 4442113037899. The reversal of 4442113037897 is 7987303112444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2278224965641 + 2163888072256 = 1509379^2 + 1471016^2 .

It is a cyclic number.

It is not a de Polignac number, because 4442113037897 - 28 = 4442113037641 is a prime.

Together with 4442113037899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4442113037899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2221056518948 + 2221056518949.

It is an arithmetic number, because the mean of its divisors is an integer number (2221056518949).

Almost surely, 24442113037897 is an apocalyptic number.

It is an amenable number.

4442113037897 is a deficient number, since it is larger than the sum of its proper divisors (1).

4442113037897 is an equidigital number, since it uses as much as digits as its factorization.

4442113037897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4064256, while the sum is 53.

The spelling of 4442113037897 in words is "four trillion, four hundred forty-two billion, one hundred thirteen million, thirty-seven thousand, eight hundred ninety-seven".