Base | Representation |
---|---|
bin | 1100111011110100101… |
… | …01101000110011001101 |
3 | 1120111011101012202002102 |
4 | 12131322111220303031 |
5 | 24240200113431411 |
6 | 540100433404445 |
7 | 44052330502661 |
oct | 6357225506315 |
9 | 1514141182072 |
10 | 444434123981 |
11 | 161535527411 |
12 | 72174109725 |
13 | 32baa2409b3 |
14 | 1772160c8a1 |
15 | b862809d3b |
hex | 677a568ccd |
444434123981 has 2 divisors, whose sum is σ = 444434123982. Its totient is φ = 444434123980.
The previous prime is 444434123941. The next prime is 444434124023. The reversal of 444434123981 is 189321434444.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 403117057225 + 41317066756 = 634915^2 + 203266^2 .
It is a cyclic number.
It is not a de Polignac number, because 444434123981 - 234 = 427254254797 is a prime.
It is a super-2 number, since 2×4444341239812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (444434123941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222217061990 + 222217061991.
It is an arithmetic number, because the mean of its divisors is an integer number (222217061991).
Almost surely, 2444434123981 is an apocalyptic number.
It is an amenable number.
444434123981 is a deficient number, since it is larger than the sum of its proper divisors (1).
444434123981 is an equidigital number, since it uses as much as digits as its factorization.
444434123981 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1327104, while the sum is 47.
The spelling of 444434123981 in words is "four hundred forty-four billion, four hundred thirty-four million, one hundred twenty-three thousand, nine hundred eighty-one".
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