4452302513441 has 2 divisors, whose sum is σ = 4452302513442. Its totient is φ = 4452302513440.

The previous prime is 4452302513437. The next prime is 4452302513447. The reversal of 4452302513441 is 1443152032544.

4452302513441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4429850487841 + 22452025600 = 2104721^2 + 149840^2 .

It is a cyclic number.

It is not a de Polignac number, because 4452302513441 - 2² = 4452302513437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4452302513395 and 4452302513404.

It is not a weakly prime, because it can be changed into another prime (4452302513447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2226151256720 + 2226151256721.

It is an arithmetic number, because the mean of its divisors is an integer number (2226151256721).

Almost surely, 2^{4452302513441} is an apocalyptic number.

It is an amenable number.

4452302513441 is a deficient number, since it is larger than the sum of its proper divisors (1).

4452302513441 is an equidigital number, since it uses as much as digits as its factorization.

4452302513441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 4452302513441 its reverse (1443152032544), we get a palindrome (5895454545985).

The spelling of 4452302513441 in words is "four trillion, four hundred fifty-two billion, three hundred two million, five hundred thirteen thousand, four hundred forty-one".