Base | Representation |
---|---|
bin | 10100011101110100010110… |
… | …00111011010010111110101 |
3 | 12220100102202220212200102011 |
4 | 22032322023013122113311 |
5 | 21344330220313203131 |
6 | 235415002344044221 |
7 | 12323334613142566 |
oct | 1216721307322765 |
9 | 186312686780364 |
10 | 45005001303541 |
11 | 13381571a59a44 |
12 | 506a32ba63671 |
13 | 1c15c51855a26 |
14 | b1837a18216d |
15 | 530a3b5510b1 |
hex | 28ee8b1da5f5 |
45005001303541 has 2 divisors, whose sum is σ = 45005001303542. Its totient is φ = 45005001303540.
The previous prime is 45005001303533. The next prime is 45005001303583. The reversal of 45005001303541 is 14530310050054.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30406908948516 + 14598092355025 = 5514246^2 + 3820745^2 .
It is a cyclic number.
It is not a de Polignac number, because 45005001303541 - 23 = 45005001303533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45005001303511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22502500651770 + 22502500651771.
It is an arithmetic number, because the mean of its divisors is an integer number (22502500651771).
Almost surely, 245005001303541 is an apocalyptic number.
It is an amenable number.
45005001303541 is a deficient number, since it is larger than the sum of its proper divisors (1).
45005001303541 is an equidigital number, since it uses as much as digits as its factorization.
45005001303541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 45005001303541 its reverse (14530310050054), we get a palindrome (59535311353595).
The spelling of 45005001303541 in words is "forty-five trillion, five billion, one million, three hundred three thousand, five hundred forty-one".
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