Base | Representation |
---|---|
bin | 10100011110110111101001… |
… | …10011000101111000110111 |
3 | 12220110220001002002220222201 |
4 | 22033123310303011320313 |
5 | 21400423220312200043 |
6 | 235443340015205331 |
7 | 12326054201635555 |
oct | 1217336463057067 |
9 | 186426032086881 |
10 | 45041134100023 |
11 | 13395923a85816 |
12 | 5075334816847 |
13 | 1c1948c671189 |
14 | b1a006cc6bd5 |
15 | 531953794c4d |
hex | 28f6f4cc5e37 |
45041134100023 has 2 divisors, whose sum is σ = 45041134100024. Its totient is φ = 45041134100022.
The previous prime is 45041134099979. The next prime is 45041134100029. The reversal of 45041134100023 is 32000143114054.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 45041134100023 - 217 = 45041133968951 is a prime.
It is a super-2 number, since 2×450411341000232 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 45041134099964 and 45041134100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45041134100029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22520567050011 + 22520567050012.
It is an arithmetic number, because the mean of its divisors is an integer number (22520567050012).
Almost surely, 245041134100023 is an apocalyptic number.
45041134100023 is a deficient number, since it is larger than the sum of its proper divisors (1).
45041134100023 is an equidigital number, since it uses as much as digits as its factorization.
45041134100023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 45041134100023 its reverse (32000143114054), we get a palindrome (77041277214077).
The spelling of 45041134100023 in words is "forty-five trillion, forty-one billion, one hundred thirty-four million, one hundred thousand, twenty-three".
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