Base | Representation |
---|---|
bin | 101010000000001111… |
… | …001011010100100111 |
3 | 11022102011202001101201 |
4 | 222000033023110213 |
5 | 1214331342311033 |
6 | 32415201503331 |
7 | 3154435215631 |
oct | 520017132447 |
9 | 138364661351 |
10 | 45101135143 |
11 | 18144462409 |
12 | 88a8341b47 |
13 | 4339b6151c |
14 | 227bc77a51 |
15 | 128e76947d |
hex | a803cb527 |
45101135143 has 4 divisors (see below), whose sum is σ = 45143564368. Its totient is φ = 45058705920.
The previous prime is 45101135141. The next prime is 45101135159. The reversal of 45101135143 is 34153110154.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 45101135143 - 21 = 45101135141 is a prime.
It is a super-3 number, since 3×451011351433 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (45101135141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21213018 + ... + 21215143.
It is an arithmetic number, because the mean of its divisors is an integer number (11285891092).
Almost surely, 245101135143 is an apocalyptic number.
45101135143 is a deficient number, since it is larger than the sum of its proper divisors (42429225).
45101135143 is a wasteful number, since it uses less digits than its factorization.
45101135143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42429224.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 45101135143 its reverse (34153110154), we get a palindrome (79254245297).
The spelling of 45101135143 in words is "forty-five billion, one hundred one million, one hundred thirty-five thousand, one hundred forty-three".
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