Base | Representation |
---|---|
bin | 101010000000110100… |
… | …110111011011011101 |
3 | 11022102212100000012021 |
4 | 222000310313123131 |
5 | 1214341404441013 |
6 | 32420153340141 |
7 | 3154615205362 |
oct | 520064673335 |
9 | 138385300167 |
10 | 45111015133 |
11 | 18149aa0398 |
12 | 88ab707651 |
13 | 433bc10582 |
14 | 227d2ca469 |
15 | 129056ba8d |
hex | a80d376dd |
45111015133 has 2 divisors, whose sum is σ = 45111015134. Its totient is φ = 45111015132.
The previous prime is 45111015083. The next prime is 45111015197. The reversal of 45111015133 is 33151011154.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44657410329 + 453604804 = 211323^2 + 21298^2 .
It is a cyclic number.
It is not a de Polignac number, because 45111015133 - 221 = 45108917981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 45111015098 and 45111015107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45111015233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22555507566 + 22555507567.
It is an arithmetic number, because the mean of its divisors is an integer number (22555507567).
Almost surely, 245111015133 is an apocalyptic number.
It is an amenable number.
45111015133 is a deficient number, since it is larger than the sum of its proper divisors (1).
45111015133 is an equidigital number, since it uses as much as digits as its factorization.
45111015133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 45111015133 its reverse (33151011154), we get a palindrome (78262026287).
The spelling of 45111015133 in words is "forty-five billion, one hundred eleven million, fifteen thousand, one hundred thirty-three".
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