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45113000831 is a prime number
BaseRepresentation
bin101010000000111100…
…011100001101111111
311022110000001220001122
4222000330130031333
51214342412011311
632420304101155
73154641115523
oct520074341577
9138400056048
1045113000831
1118150127268
1288b03047bb
13433c457342
14227d685d83
1512908100db
hexa80f1c37f

45113000831 has 2 divisors, whose sum is σ = 45113000832. Its totient is φ = 45113000830.

The previous prime is 45113000819. The next prime is 45113000879. The reversal of 45113000831 is 13800031154.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-45113000831 is a prime.

It is a super-2 number, since 2×451130008312 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 45113000831.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45113005831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22556500415 + 22556500416.

It is an arithmetic number, because the mean of its divisors is an integer number (22556500416).

Almost surely, 245113000831 is an apocalyptic number.

45113000831 is a deficient number, since it is larger than the sum of its proper divisors (1).

45113000831 is an equidigital number, since it uses as much as digits as its factorization.

45113000831 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 45113000831 its reverse (13800031154), we get a palindrome (58913031985).

The spelling of 45113000831 in words is "forty-five billion, one hundred thirteen million, eight hundred thirty-one", and thus it is an aban number.