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45313223503 = 49879086269
BaseRepresentation
bin101010001100111000…
…001110101101001111
311022221221211020221011
4222030320032231033
51220300141123003
632452215350051
73162622021222
oct521470165517
9138857736834
1045313223503
1118243151549
128947382327
134371a8bab2
14229c0c55b9
1512a31b046d
hexa8ce0eb4f

45313223503 has 4 divisors (see below), whose sum is σ = 45322314760. Its totient is φ = 45304132248.

The previous prime is 45313223471. The next prime is 45313223537. The reversal of 45313223503 is 30532231354.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 45313223503 - 25 = 45313223471 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (45313223573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4538148 + ... + 4548121.

It is an arithmetic number, because the mean of its divisors is an integer number (11330578690).

Almost surely, 245313223503 is an apocalyptic number.

45313223503 is a deficient number, since it is larger than the sum of its proper divisors (9091257).

45313223503 is an equidigital number, since it uses as much as digits as its factorization.

45313223503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9091256.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 45313223503 its reverse (30532231354), we get a palindrome (75845454857).

The spelling of 45313223503 in words is "forty-five billion, three hundred thirteen million, two hundred twenty-three thousand, five hundred three".

Divisors: 1 4987 9086269 45313223503