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454255442113 = 1141295949283
BaseRepresentation
bin1101001110000111011…
…10111111100011000001
31121102111211202101202211
412213003232333203001
524420303343121423
6544403154342121
744550605356354
oct6470356774301
91542454671684
10454255442113
1116571539a060
127405528a941
1333ab3bc9245
1417db3b3c29b
15bc39b7010d
hex69c3bbf8c1

454255442113 has 4 divisors (see below), whose sum is σ = 495551391408. Its totient is φ = 412959492820.

The previous prime is 454255442111. The next prime is 454255442131. The reversal of 454255442113 is 311244552454.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 454255442113 - 21 = 454255442111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (454255442111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20647974631 + ... + 20647974652.

It is an arithmetic number, because the mean of its divisors is an integer number (123887847852).

Almost surely, 2454255442113 is an apocalyptic number.

It is an amenable number.

454255442113 is a deficient number, since it is larger than the sum of its proper divisors (41295949295).

454255442113 is a wasteful number, since it uses less digits than its factorization.

454255442113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41295949294.

The product of its digits is 384000, while the sum is 40.

Adding to 454255442113 its reverse (311244552454), we get a palindrome (765499994567).

The spelling of 454255442113 in words is "four hundred fifty-four billion, two hundred fifty-five million, four hundred forty-two thousand, one hundred thirteen".

Divisors: 1 11 41295949283 454255442113