Base | Representation |
---|---|
bin | 101010011000100111… |
… | …000011111000010111 |
3 | 11100110200012001011121 |
4 | 222120213003320113 |
5 | 1221201033034203 |
6 | 32523530144411 |
7 | 3200532015325 |
oct | 523047037027 |
9 | 140420161147 |
10 | 45510049303 |
11 | 183342666a4 |
12 | 89a1282107 |
13 | 43a37a4374 |
14 | 22ba2bcd15 |
15 | 12b55de0bd |
hex | a989c3e17 |
45510049303 has 2 divisors, whose sum is σ = 45510049304. Its totient is φ = 45510049302.
The previous prime is 45510049297. The next prime is 45510049327. The reversal of 45510049303 is 30394001554.
45510049303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-45510049303 is a prime.
It is a super-2 number, since 2×455100493032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45510041303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22755024651 + 22755024652.
It is an arithmetic number, because the mean of its divisors is an integer number (22755024652).
Almost surely, 245510049303 is an apocalyptic number.
45510049303 is a deficient number, since it is larger than the sum of its proper divisors (1).
45510049303 is an equidigital number, since it uses as much as digits as its factorization.
45510049303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
The spelling of 45510049303 in words is "forty-five billion, five hundred ten million, forty-nine thousand, three hundred three".
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