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45532065433 is a prime number
BaseRepresentation
bin101010011001111011…
…000010111010011001
311100112012121120121211
4222121323002322121
51221222202043213
632530034103121
73201220112311
oct523173027231
9140465546554
1045532065433
1118345733748
1289a871aaa1
1343a821236a
1422bd1b0441
1512b74dc53d
hexa99ec2e99

45532065433 has 2 divisors, whose sum is σ = 45532065434. Its totient is φ = 45532065432.

The previous prime is 45532065427. The next prime is 45532065473. The reversal of 45532065433 is 33456023554.

It is an a-pointer prime, because the next prime (45532065473) can be obtained adding 45532065433 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23572382089 + 21959683344 = 153533^2 + 148188^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-45532065433 is a prime.

It is not a weakly prime, because it can be changed into another prime (45532065473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22766032716 + 22766032717.

It is an arithmetic number, because the mean of its divisors is an integer number (22766032717).

Almost surely, 245532065433 is an apocalyptic number.

It is an amenable number.

45532065433 is a deficient number, since it is larger than the sum of its proper divisors (1).

45532065433 is an equidigital number, since it uses as much as digits as its factorization.

45532065433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 40.

Adding to 45532065433 its reverse (33456023554), we get a palindrome (78988088987).

The spelling of 45532065433 in words is "forty-five billion, five hundred thirty-two million, sixty-five thousand, four hundred thirty-three".