Base | Representation |
---|---|
bin | 101011010100011001… |
… | …111111001011101011 |
3 | 11110001120220011212121 |
4 | 223110121333023223 |
5 | 1230224343131042 |
6 | 33211244252111 |
7 | 3234433100602 |
oct | 532431771353 |
9 | 143046804777 |
10 | 46513255147 |
11 | 187a957a037 |
12 | 9021241037 |
13 | 45035947a8 |
14 | 2373622a39 |
15 | 1323705367 |
hex | ad467f2eb |
46513255147 has 2 divisors, whose sum is σ = 46513255148. Its totient is φ = 46513255146.
The previous prime is 46513255141. The next prime is 46513255153. The reversal of 46513255147 is 74155231564.
It is a balanced prime because it is at equal distance from previous prime (46513255141) and next prime (46513255153).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-46513255147 is a prime.
It is not a weakly prime, because it can be changed into another prime (46513255141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23256627573 + 23256627574.
It is an arithmetic number, because the mean of its divisors is an integer number (23256627574).
Almost surely, 246513255147 is an apocalyptic number.
46513255147 is a deficient number, since it is larger than the sum of its proper divisors (1).
46513255147 is an equidigital number, since it uses as much as digits as its factorization.
46513255147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 504000, while the sum is 43.
The spelling of 46513255147 in words is "forty-six billion, five hundred thirteen million, two hundred fifty-five thousand, one hundred forty-seven".
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