Base | Representation |
---|---|
bin | 100001110110101110010… |
… | …1110101001100111010001 |
3 | 121110211012221101201112011 |
4 | 1003231130232221213101 |
5 | 1102213323330031023 |
6 | 13521321112102521 |
7 | 660111544412563 |
oct | 103553456514721 |
9 | 17424187351464 |
10 | 4653005314513 |
11 | 1534368218516 |
12 | 63194a094a41 |
13 | 279a1301b16a |
14 | 1212c7101333 |
15 | 8107e46150d |
hex | 43b5cba99d1 |
4653005314513 has 2 divisors, whose sum is σ = 4653005314514. Its totient is φ = 4653005314512.
The previous prime is 4653005314501. The next prime is 4653005314519. The reversal of 4653005314513 is 3154135003564.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4620234177729 + 32771136784 = 2149473^2 + 181028^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4653005314513 is a prime.
It is not a weakly prime, because it can be changed into another prime (4653005314519) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2326502657256 + 2326502657257.
It is an arithmetic number, because the mean of its divisors is an integer number (2326502657257).
Almost surely, 24653005314513 is an apocalyptic number.
It is an amenable number.
4653005314513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4653005314513 is an equidigital number, since it uses as much as digits as its factorization.
4653005314513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 4653005314513 in words is "four trillion, six hundred fifty-three billion, five million, three hundred fourteen thousand, five hundred thirteen".
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