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465341512117 is a prime number
BaseRepresentation
bin1101100010110001000…
…00111111100110110101
31122111010110011002212011
412301120200333212311
530111004411341432
6553435215324221
745422411406226
oct6613040774665
91574113132764
10465341512117
1116a394174589
1276229b20671
1334b5c8caa91
141874621524d
15c188061847
hex6c5883f9b5

465341512117 has 2 divisors, whose sum is σ = 465341512118. Its totient is φ = 465341512116.

The previous prime is 465341512109. The next prime is 465341512123. The reversal of 465341512117 is 711215143564.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 464893512561 + 447999556 = 681831^2 + 21166^2 .

It is a cyclic number.

It is not a de Polignac number, because 465341512117 - 23 = 465341512109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 465341512117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (465341512187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 232670756058 + 232670756059.

It is an arithmetic number, because the mean of its divisors is an integer number (232670756059).

Almost surely, 2465341512117 is an apocalyptic number.

It is an amenable number.

465341512117 is a deficient number, since it is larger than the sum of its proper divisors (1).

465341512117 is an equidigital number, since it uses as much as digits as its factorization.

465341512117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 100800, while the sum is 40.

The spelling of 465341512117 in words is "four hundred sixty-five billion, three hundred forty-one million, five hundred twelve thousand, one hundred seventeen".