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470212212013 is a prime number
BaseRepresentation
bin1101101011110101101…
…01001111010100101101
31122221200220020022000121
412311322311033110231
530200443311241023
61000002411324541
745654203566405
oct6657265172455
91587626208017
10470212212013
111714635984a5
1277169150751
1335457a2761b
1418a89059805
15c370976d5d
hex6d7ad4f52d

470212212013 has 2 divisors, whose sum is σ = 470212212014. Its totient is φ = 470212212012.

The previous prime is 470212211941. The next prime is 470212212023. The reversal of 470212212013 is 310212212074.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 415866345129 + 54345866884 = 644877^2 + 233122^2 .

It is a cyclic number.

It is not a de Polignac number, because 470212212013 - 221 = 470210114861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (470212212023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235106106006 + 235106106007.

It is an arithmetic number, because the mean of its divisors is an integer number (235106106007).

Almost surely, 2470212212013 is an apocalyptic number.

It is an amenable number.

470212212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

470212212013 is an equidigital number, since it uses as much as digits as its factorization.

470212212013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 470212212013 its reverse (310212212074), we get a palindrome (780424424087).

The spelling of 470212212013 in words is "four hundred seventy billion, two hundred twelve million, two hundred twelve thousand, thirteen".