4711053433 has 2 divisors, whose sum is σ = 4711053434. Its totient is φ = 4711053432.

The previous prime is 4711053371. The next prime is 4711053493. The reversal of 4711053433 is 3343501174.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3724905024 + 986148409 = 61032^2 + 31403^2 .

It is a cyclic number.

It is not a de Polignac number, because 4711053433 - 2²⁹ = 4174182521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4711053395 and 4711053404.

It is not a weakly prime, because it can be changed into another prime (4711053493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2355526716 + 2355526717.

It is an arithmetic number, because the mean of its divisors is an integer number (2355526717).

Almost surely, 2^4711053433 is an apocalyptic number.

It is an amenable number.

4711053433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4711053433 is an equidigital number, since it uses as much as digits as its factorization.

4711053433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

The square root of 4711053433 is about 68637.1141074565. The cubic root of 4711053433 is about 1676.3807945033.

The spelling of 4711053433 in words is "four billion, seven hundred eleven million, fifty-three thousand, four hundred thirty-three".