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4711105348693 is a prime number
BaseRepresentation
bin100010010001110001111…
…0000101100010001010101
3121200101012000212021010221
41010203203300230101111
51104141320432124233
614004130225314341
7664236403512412
oct104434360542125
917611160767127
104711105348693
111556a72173097
126410637959b1
13282341c57203
141240394d9109
158282eeb142d
hex448e3c2c455

4711105348693 has 2 divisors, whose sum is σ = 4711105348694. Its totient is φ = 4711105348692.

The previous prime is 4711105348661. The next prime is 4711105348709. The reversal of 4711105348693 is 3968435011174.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4407908648004 + 303196700689 = 2099502^2 + 550633^2 .

It is a cyclic number.

It is not a de Polignac number, because 4711105348693 - 25 = 4711105348661 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4711105348693.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4711105348093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2355552674346 + 2355552674347.

It is an arithmetic number, because the mean of its divisors is an integer number (2355552674347).

Almost surely, 24711105348693 is an apocalyptic number.

It is an amenable number.

4711105348693 is a deficient number, since it is larger than the sum of its proper divisors (1).

4711105348693 is an equidigital number, since it uses as much as digits as its factorization.

4711105348693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 52.

The spelling of 4711105348693 in words is "four trillion, seven hundred eleven billion, one hundred five million, three hundred forty-eight thousand, six hundred ninety-three".