Base | Representation |
---|---|
bin | 1101101101101111011… |
… | …11000111011100011101 |
3 | 1200001100002221101000201 |
4 | 12312313233013130131 |
5 | 30210041402021203 |
6 | 1000252032223501 |
7 | 46021422025012 |
oct | 6666757073435 |
9 | 1601302841021 |
10 | 471234017053 |
11 | 171938354778 |
12 | 773b339ab91 |
13 | 3558b62a6a7 |
14 | 18b44a41709 |
15 | c3d0513e1d |
hex | 6db7bc771d |
471234017053 has 2 divisors, whose sum is σ = 471234017054. Its totient is φ = 471234017052.
The previous prime is 471234017041. The next prime is 471234017069. The reversal of 471234017053 is 350710432174.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 302459301369 + 168774715684 = 549963^2 + 410822^2 .
It is a cyclic number.
It is not a de Polignac number, because 471234017053 - 217 = 471233885981 is a prime.
It is a super-2 number, since 2×4712340170532 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (471234017153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235617008526 + 235617008527.
It is an arithmetic number, because the mean of its divisors is an integer number (235617008527).
Almost surely, 2471234017053 is an apocalyptic number.
It is an amenable number.
471234017053 is a deficient number, since it is larger than the sum of its proper divisors (1).
471234017053 is an equidigital number, since it uses as much as digits as its factorization.
471234017053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70560, while the sum is 37.
The spelling of 471234017053 in words is "four hundred seventy-one billion, two hundred thirty-four million, seventeen thousand, fifty-three".
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