Base | Representation |
---|---|
bin | 10101011100110010010011… |
… | …11110110101011110001111 |
3 | 20012000021022212221120022121 |
4 | 22232121021332311132033 |
5 | 22140302213421202031 |
6 | 244152535353553411 |
7 | 12635550121112365 |
oct | 1256311176653617 |
9 | 205007285846277 |
10 | 47168572053391 |
11 | 14036096273118 |
12 | 5359703415867 |
13 | 2041c92065239 |
14 | b90d8487d635 |
15 | 56be69701011 |
hex | 2ae649fb578f |
47168572053391 has 2 divisors, whose sum is σ = 47168572053392. Its totient is φ = 47168572053390.
The previous prime is 47168572053373. The next prime is 47168572053413. The reversal of 47168572053391 is 19335027586174.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 47168572053391 - 29 = 47168572052879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47168572053311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23584286026695 + 23584286026696.
It is an arithmetic number, because the mean of its divisors is an integer number (23584286026696).
It is a 1-persistent number, because it is pandigital, but 2⋅47168572053391 = 94337144106782 is not.
Almost surely, 247168572053391 is an apocalyptic number.
47168572053391 is a deficient number, since it is larger than the sum of its proper divisors (1).
47168572053391 is an equidigital number, since it uses as much as digits as its factorization.
47168572053391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38102400, while the sum is 61.
The spelling of 47168572053391 in words is "forty-seven trillion, one hundred sixty-eight billion, five hundred seventy-two million, fifty-three thousand, three hundred ninety-one".
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