Base | Representation |
---|---|
bin | 101100000000000011… |
… | …010101000111000001 |
3 | 11111221121202202000111 |
4 | 230000003111013001 |
5 | 1233224322410103 |
6 | 33412043151321 |
7 | 3261534143566 |
oct | 540003250701 |
9 | 144847682014 |
10 | 47245513153 |
11 | 19044951343 |
12 | 91a6515541 |
13 | 45bc1b9857 |
14 | 240299686d |
15 | 1367b4a86d |
hex | b000d51c1 |
47245513153 has 2 divisors, whose sum is σ = 47245513154. Its totient is φ = 47245513152.
The previous prime is 47245513151. The next prime is 47245513163. The reversal of 47245513153 is 35131554274.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28489388944 + 18756124209 = 168788^2 + 136953^2 .
It is a cyclic number.
It is not a de Polignac number, because 47245513153 - 21 = 47245513151 is a prime.
Together with 47245513151, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (47245513151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23622756576 + 23622756577.
It is an arithmetic number, because the mean of its divisors is an integer number (23622756577).
Almost surely, 247245513153 is an apocalyptic number.
It is an amenable number.
47245513153 is a deficient number, since it is larger than the sum of its proper divisors (1).
47245513153 is an equidigital number, since it uses as much as digits as its factorization.
47245513153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 252000, while the sum is 40.
The spelling of 47245513153 in words is "forty-seven billion, two hundred forty-five million, five hundred thirteen thousand, one hundred fifty-three".
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