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473316074857 is a prime number
BaseRepresentation
bin1101110001100111101…
…01100010010101101001
31200020201012200212101201
412320303311202111221
530223322403343412
61001234410044201
746124133153253
oct6706365422551
91606635625351
10473316074857
111728066485aa
1277894719661
1335830aa5962
1418ca137acd3
15c4a31d4e57
hex6e33d62569

473316074857 has 2 divisors, whose sum is σ = 473316074858. Its totient is φ = 473316074856.

The previous prime is 473316074851. The next prime is 473316074863. The reversal of 473316074857 is 758470613374.

It is a balanced prime because it is at equal distance from previous prime (473316074851) and next prime (473316074863).

It can be written as a sum of positive squares in only one way, i.e., 419986948096 + 53329126761 = 648064^2 + 230931^2 .

It is a cyclic number.

It is not a de Polignac number, because 473316074857 - 211 = 473316072809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 473316074798 and 473316074807.

It is not a weakly prime, because it can be changed into another prime (473316074851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 236658037428 + 236658037429.

It is an arithmetic number, because the mean of its divisors is an integer number (236658037429).

Almost surely, 2473316074857 is an apocalyptic number.

It is an amenable number.

473316074857 is a deficient number, since it is larger than the sum of its proper divisors (1).

473316074857 is an equidigital number, since it uses as much as digits as its factorization.

473316074857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11854080, while the sum is 55.

The spelling of 473316074857 in words is "four hundred seventy-three billion, three hundred sixteen million, seventy-four thousand, eight hundred fifty-seven".