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473545008021011 is a prime number
BaseRepresentation
bin110101110101011111100100…
…1111111001111111000010011
32022002200110102210220020110012
41223222333021333033320103
5444032030134023133021
64355051323511225135
7201513332514405233
oct15352771177177023
92262613383806405
10473545008021011
1112798234580a273
12451402410781ab
13174301446913c4
1484d19b4945cc3
1539b2ed447135b
hex1aeafc9fcfe13

473545008021011 has 2 divisors, whose sum is σ = 473545008021012. Its totient is φ = 473545008021010.

The previous prime is 473545008020911. The next prime is 473545008021013. The reversal of 473545008021011 is 110120800545374.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 473545008021011 - 222 = 473545003826707 is a prime.

Together with 473545008021013, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 473545008021011.

It is not a weakly prime, because it can be changed into another prime (473545008021013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 236772504010505 + 236772504010506.

It is an arithmetic number, because the mean of its divisors is an integer number (236772504010506).

Almost surely, 2473545008021011 is an apocalyptic number.

473545008021011 is a deficient number, since it is larger than the sum of its proper divisors (1).

473545008021011 is an equidigital number, since it uses as much as digits as its factorization.

473545008021011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 41.

Adding to 473545008021011 its reverse (110120800545374), we get a palindrome (583665808566385).

The spelling of 473545008021011 in words is "four hundred seventy-three trillion, five hundred forty-five billion, eight million, twenty-one thousand, eleven".