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4744623695113 is a prime number
BaseRepresentation
bin100010100001011000110…
…0111000010010100001001
3121210120200222112200110201
41011002301213002110021
51110213442131220423
614031352224012201
7666534124662121
oct105026147022411
917716628480421
104744623695113
11156a202424935
12647658a61061
132855542104a3
141258d8d19c81
158364291d2ad
hex450b19c2509

4744623695113 has 2 divisors, whose sum is σ = 4744623695114. Its totient is φ = 4744623695112.

The previous prime is 4744623695111. The next prime is 4744623695131. The reversal of 4744623695113 is 3115963264474.

Together with next prime (4744623695131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4111052270329 + 633571424784 = 2027573^2 + 795972^2 .

It is a cyclic number.

It is not a de Polignac number, because 4744623695113 - 21 = 4744623695111 is a prime.

It is a super-2 number, since 2×47446236951132 (a number of 26 digits) contains 22 as substring.

Together with 4744623695111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (4744623695111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2372311847556 + 2372311847557.

It is an arithmetic number, because the mean of its divisors is an integer number (2372311847557).

Almost surely, 24744623695113 is an apocalyptic number.

It is an amenable number.

4744623695113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4744623695113 is an equidigital number, since it uses as much as digits as its factorization.

4744623695113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13063680, while the sum is 55.

The spelling of 4744623695113 in words is "four trillion, seven hundred forty-four billion, six hundred twenty-three million, six hundred ninety-five thousand, one hundred thirteen".