Base | Representation |
---|---|
bin | 100010100011011000111… |
… | …0011000010101011001101 |
3 | 121210222210112012112010122 |
4 | 1011012301303002223031 |
5 | 1110301242440401423 |
6 | 14033342523314325 |
7 | 1000045465233152 |
oct | 105066163025315 |
9 | 17728715175118 |
10 | 4748921809613 |
11 | 1571008614983 |
12 | 64845837b9a5 |
13 | 285a8a81c6c7 |
14 | 125bc5ab2229 |
15 | 837e4e2d8c8 |
hex | 451b1cc2acd |
4748921809613 has 2 divisors, whose sum is σ = 4748921809614. Its totient is φ = 4748921809612.
The previous prime is 4748921809573. The next prime is 4748921809637. The reversal of 4748921809613 is 3169081298474.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4298730462244 + 450191347369 = 2073338^2 + 670963^2 .
It is a cyclic number.
It is not a de Polignac number, because 4748921809613 - 26 = 4748921809549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4748921806613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2374460904806 + 2374460904807.
It is an arithmetic number, because the mean of its divisors is an integer number (2374460904807).
Almost surely, 24748921809613 is an apocalyptic number.
It is an amenable number.
4748921809613 is a deficient number, since it is larger than the sum of its proper divisors (1).
4748921809613 is an equidigital number, since it uses as much as digits as its factorization.
4748921809613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20901888, while the sum is 62.
The spelling of 4748921809613 in words is "four trillion, seven hundred forty-eight billion, nine hundred twenty-one million, eight hundred nine thousand, six hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •