Base | Representation |
---|---|
bin | 10101101010001010101001… |
… | …00001001101001110011101 |
3 | 20020122012222211122010212020 |
4 | 22311011110201031032131 |
5 | 22220320234421231123 |
6 | 245144051012530353 |
7 | 13014013634046012 |
oct | 1265052441151635 |
9 | 206565884563766 |
10 | 47628310336413 |
11 | 141a3064576754 |
12 | 54128289209b9 |
13 | 207643ab47b31 |
14 | ba9318849709 |
15 | 578dc58a17e3 |
hex | 2b515484d39d |
47628310336413 has 4 divisors (see below), whose sum is σ = 63504413781888. Its totient is φ = 31752206890940.
The previous prime is 47628310336403. The next prime is 47628310336417. The reversal of 47628310336413 is 31463301382674.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 47628310336413 - 218 = 47628310074269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (47628310336417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7938051722733 + ... + 7938051722738.
It is an arithmetic number, because the mean of its divisors is an integer number (15876103445472).
Almost surely, 247628310336413 is an apocalyptic number.
It is an amenable number.
47628310336413 is a deficient number, since it is larger than the sum of its proper divisors (15876103445475).
47628310336413 is a wasteful number, since it uses less digits than its factorization.
47628310336413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15876103445474.
The product of its (nonzero) digits is 5225472, while the sum is 51.
The spelling of 47628310336413 in words is "forty-seven trillion, six hundred twenty-eight billion, three hundred ten million, three hundred thirty-six thousand, four hundred thirteen".
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