Base | Representation |
---|---|
bin | 100010101010100100010… |
… | …0111010101011000011101 |
3 | 121212110120211121102201111 |
4 | 1011111020213111120131 |
5 | 1111024330233031023 |
6 | 14044412312342021 |
7 | 1001132466221101 |
oct | 105251047253035 |
9 | 17773524542644 |
10 | 4764337002013 |
11 | 15775a9039106 |
12 | 64b43a9a4911 |
13 | 287376399124 |
14 | 1268490d3901 |
15 | 83de840800d |
hex | 455489d561d |
4764337002013 has 2 divisors, whose sum is σ = 4764337002014. Its totient is φ = 4764337002012.
The previous prime is 4764337001839. The next prime is 4764337002067. The reversal of 4764337002013 is 3102007334674.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3341426793849 + 1422910208164 = 1827957^2 + 1192858^2 .
It is a cyclic number.
It is not a de Polignac number, because 4764337002013 - 217 = 4764336870941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4764337002613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2382168501006 + 2382168501007.
It is an arithmetic number, because the mean of its divisors is an integer number (2382168501007).
Almost surely, 24764337002013 is an apocalyptic number.
It is an amenable number.
4764337002013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4764337002013 is an equidigital number, since it uses as much as digits as its factorization.
4764337002013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 254016, while the sum is 40.
The spelling of 4764337002013 in words is "four trillion, seven hundred sixty-four billion, three hundred thirty-seven million, two thousand, thirteen".
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