Base | Representation |
---|---|
bin | 101100011000000100… |
… | …110011010111110001 |
3 | 11112222201011020222020 |
4 | 230120010303113301 |
5 | 1240041012134213 |
6 | 33520041502053 |
7 | 3304530004326 |
oct | 543004632761 |
9 | 145881136866 |
10 | 47648552433 |
11 | 19231402759 |
12 | 92994a1929 |
13 | 4654853631 |
14 | 244030cb4d |
15 | 138d20e923 |
hex | b181335f1 |
47648552433 has 4 divisors (see below), whose sum is σ = 63531403248. Its totient is φ = 31765701620.
The previous prime is 47648552417. The next prime is 47648552503. The reversal of 47648552433 is 33425584674.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 47648552433 - 24 = 47648552417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (47648052433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7941425403 + ... + 7941425408.
It is an arithmetic number, because the mean of its divisors is an integer number (15882850812).
Almost surely, 247648552433 is an apocalyptic number.
It is an amenable number.
47648552433 is a deficient number, since it is larger than the sum of its proper divisors (15882850815).
47648552433 is a wasteful number, since it uses less digits than its factorization.
47648552433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15882850814.
The product of its digits is 9676800, while the sum is 51.
The spelling of 47648552433 in words is "forty-seven billion, six hundred forty-eight million, five hundred fifty-two thousand, four hundred thirty-three".
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