Base | Representation |
---|---|
bin | 1000111000011000… |
… | …11110100011010101 |
3 | 110022021211111200111 |
4 | 10130030132203111 |
5 | 34231102001323 |
6 | 2105042443021 |
7 | 226104222154 |
oct | 43414364325 |
9 | 13267744614 |
10 | 4768000213 |
11 | 2027459149 |
12 | b10963471 |
13 | 5aca7c302 |
14 | 33334d59b |
15 | 1cd8cac0d |
hex | 11c31e8d5 |
4768000213 has 2 divisors, whose sum is σ = 4768000214. Its totient is φ = 4768000212.
The previous prime is 4768000199. The next prime is 4768000231. The reversal of 4768000213 is 3120008674.
Together with next prime (4768000231) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4019813604 + 748186609 = 63402^2 + 27353^2 .
It is a cyclic number.
It is not a de Polignac number, because 4768000213 - 29 = 4767999701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4768000253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2384000106 + 2384000107.
It is an arithmetic number, because the mean of its divisors is an integer number (2384000107).
Almost surely, 24768000213 is an apocalyptic number.
It is an amenable number.
4768000213 is a deficient number, since it is larger than the sum of its proper divisors (1).
4768000213 is an equidigital number, since it uses as much as digits as its factorization.
4768000213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The square root of 4768000213 is about 69050.7075488731. The cubic root of 4768000213 is about 1683.1084048535.
Adding to 4768000213 its reverse (3120008674), we get a palindrome (7888008887).
The spelling of 4768000213 in words is "four billion, seven hundred sixty-eight million, two hundred thirteen", and thus it is an aban number.
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