4770444013 has 4 divisors (see below), whose sum is σ = 4886796348. Its totient is φ = 4654091680.

The previous prime is 4770443987. The next prime is 4770444017. The reversal of 4770444013 is 3104440774.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3104440774 = 2 ⋅1552220387.

It can be written as a sum of positive squares in 2 ways, for example, as 1548973449 + 3221470564 = 39357^2 + 56758^2 .

It is a cyclic number.

It is not a de Polignac number, because 4770444013 - 2¹³ = 4770435821 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4770444013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4770444017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58176106 + ... + 58176187.

It is an arithmetic number, because the mean of its divisors is an integer number (1221699087).

Almost surely, 2^4770444013 is an apocalyptic number.

It is an amenable number.

4770444013 is a deficient number, since it is larger than the sum of its proper divisors (116352335).

4770444013 is a wasteful number, since it uses less digits than its factorization.

4770444013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116352334.

The product of its (nonzero) digits is 37632, while the sum is 34.

The square root of 4770444013 is about 69068.4009732381. The cubic root of 4770444013 is about 1683.3959102792.

Adding to 4770444013 its reverse (3104440774), we get a palindrome (7874884787).

The spelling of 4770444013 in words is "four billion, seven hundred seventy million, four hundred forty-four thousand, thirteen".