Base | Representation |
---|---|
bin | 101100100111110111… |
… | …101000110010110001 |
3 | 11120200011202212000221 |
4 | 230213313220302301 |
5 | 1241111331133224 |
6 | 34002225213041 |
7 | 3314225225224 |
oct | 544767506261 |
9 | 146604685027 |
10 | 47913536689 |
11 | 19357a40307 |
12 | 9352191181 |
13 | 4697711455 |
14 | 24675a95bb |
15 | 13a66036e4 |
hex | b27de8cb1 |
47913536689 has 2 divisors, whose sum is σ = 47913536690. Its totient is φ = 47913536688.
The previous prime is 47913536677. The next prime is 47913536701. The reversal of 47913536689 is 98663531974.
It is a balanced prime because it is at equal distance from previous prime (47913536677) and next prime (47913536701).
It can be written as a sum of positive squares in only one way, i.e., 34864358400 + 13049178289 = 186720^2 + 114233^2 .
It is a cyclic number.
It is not a de Polignac number, because 47913536689 - 231 = 45766053041 is a prime.
It is not a weakly prime, because it can be changed into another prime (47913536609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23956768344 + 23956768345.
It is an arithmetic number, because the mean of its divisors is an integer number (23956768345).
Almost surely, 247913536689 is an apocalyptic number.
It is an amenable number.
47913536689 is a deficient number, since it is larger than the sum of its proper divisors (1).
47913536689 is an equidigital number, since it uses as much as digits as its factorization.
47913536689 is an evil number, because the sum of its binary digits is even.
The product of its digits is 29393280, while the sum is 61.
The spelling of 47913536689 in words is "forty-seven billion, nine hundred thirteen million, five hundred thirty-six thousand, six hundred eighty-nine".
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