Base | Representation |
---|---|
bin | 10101110101000001011111… |
… | …01011100011000011110111 |
3 | 20021221212212220221100111011 |
4 | 22322200233223203003313 |
5 | 22242423233214220142 |
6 | 250031303502453051 |
7 | 13052661211463323 |
oct | 1272405753430367 |
9 | 207855786840434 |
10 | 48001354445047 |
11 | 14327295211983 |
12 | 5472b98594187 |
13 | 20a267b97a2a3 |
14 | bbd3c69ac983 |
15 | 58395aa29417 |
hex | 2ba82fae30f7 |
48001354445047 has 4 divisors (see below), whose sum is σ = 48001374305200. Its totient is φ = 48001334584896.
The previous prime is 48001354445039. The next prime is 48001354445089. The reversal of 48001354445047 is 74054445310084.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 48001354445047 - 23 = 48001354445039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48001354443047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5705547 + ... + 11338252.
It is an arithmetic number, because the mean of its divisors is an integer number (12000343576300).
Almost surely, 248001354445047 is an apocalyptic number.
48001354445047 is a deficient number, since it is larger than the sum of its proper divisors (19860153).
48001354445047 is a wasteful number, since it uses less digits than its factorization.
48001354445047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19860152.
The product of its (nonzero) digits is 4300800, while the sum is 49.
The spelling of 48001354445047 in words is "forty-eight trillion, one billion, three hundred fifty-four million, four hundred forty-five thousand, forty-seven".
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