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48080376673397 is a prime number
BaseRepresentation
bin10101110111010100101011…
…10001011011010001110101
320022020102212010012110221022
422323222111301123101311
522300222102412022042
6250131453051230525
713061456361363605
oct1273522561332165
9208212763173838
1048080376673397
11143578561a7712
125486370a48445
1320a9c633586a3
14bc3161944c05
15585a33257cd2
hex2bba95c5b475

48080376673397 has 2 divisors, whose sum is σ = 48080376673398. Its totient is φ = 48080376673396.

The previous prime is 48080376673391. The next prime is 48080376673457. The reversal of 48080376673397 is 79337667308084.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26935747081156 + 21144629592241 = 5189966^2 + 4598329^2 .

It is a cyclic number.

It is not a de Polignac number, because 48080376673397 - 218 = 48080376411253 is a prime.

It is a super-3 number, since 3×480803766733973 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 48080376673397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48080376673391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24040188336698 + 24040188336699.

It is an arithmetic number, because the mean of its divisors is an integer number (24040188336699).

Almost surely, 248080376673397 is an apocalyptic number.

It is an amenable number.

48080376673397 is a deficient number, since it is larger than the sum of its proper divisors (1).

48080376673397 is an equidigital number, since it uses as much as digits as its factorization.

48080376673397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768144384, while the sum is 71.

The spelling of 48080376673397 in words is "forty-eight trillion, eighty billion, three hundred seventy-six million, six hundred seventy-three thousand, three hundred ninety-seven".