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48080376804133 is a prime number
BaseRepresentation
bin10101110111010100101011…
…10001111011001100100101
320022020102212010110010021101
422323222111301323030211
522300222102430213013
6250131453054120101
713061456362450012
oct1273522561731445
9208212763403241
1048080376804133
1114357856286963
125486370ab0031
1320a9c633a304b
14bc316197a709
15585a332818dd
hex2bba95c7b325

48080376804133 has 2 divisors, whose sum is σ = 48080376804134. Its totient is φ = 48080376804132.

The previous prime is 48080376804079. The next prime is 48080376804193. The reversal of 48080376804133 is 33140867308084.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47568360708324 + 512016095809 = 6896982^2 + 715553^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48080376804133 is a prime.

It is a super-3 number, since 3×480803768041333 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48080376804193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24040188402066 + 24040188402067.

It is an arithmetic number, because the mean of its divisors is an integer number (24040188402067).

Almost surely, 248080376804133 is an apocalyptic number.

It is an amenable number.

48080376804133 is a deficient number, since it is larger than the sum of its proper divisors (1).

48080376804133 is an equidigital number, since it uses as much as digits as its factorization.

48080376804133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9289728, while the sum is 55.

The spelling of 48080376804133 in words is "forty-eight trillion, eighty billion, three hundred seventy-six million, eight hundred four thousand, one hundred thirty-three".