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48081154543307 is a prime number
BaseRepresentation
bin10101110111010110001000…
…01000110000111011001011
320022020111212022220100211222
422323223010020300323023
522300230201030341212
6250132102155512255
713061514555230114
oct1273530410607313
9208214768810758
1048081154543307
11143581152a2906
12548654945868b
1320aa058560742
14bc31d6d8d20b
15585a7b6acc72
hex2bbac4230ecb

48081154543307 has 2 divisors, whose sum is σ = 48081154543308. Its totient is φ = 48081154543306.

The previous prime is 48081154543273. The next prime is 48081154543333. The reversal of 48081154543307 is 70334545118084.

48081154543307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 48081154543307 - 216 = 48081154477771 is a prime.

It is a super-3 number, since 3×480811545433073 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (48081154548307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24040577271653 + 24040577271654.

It is an arithmetic number, because the mean of its divisors is an integer number (24040577271654).

Almost surely, 248081154543307 is an apocalyptic number.

48081154543307 is a deficient number, since it is larger than the sum of its proper divisors (1).

48081154543307 is an equidigital number, since it uses as much as digits as its factorization.

48081154543307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6451200, while the sum is 53.

The spelling of 48081154543307 in words is "forty-eight trillion, eighty-one billion, one hundred fifty-four million, five hundred forty-three thousand, three hundred seven".