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48100433 is a prime number
BaseRepresentation
bin1011011101111…
…1010001010001
310100111202101112
42313133101101
544303203213
64434543105
71122563333
oct267372121
9110452345
1048100433
1125173627
1214137a95
139c718c4
146561453
154351ea8
hex2ddf451

48100433 has 2 divisors, whose sum is σ = 48100434. Its totient is φ = 48100432.

The previous prime is 48100397. The next prime is 48100447. The reversal of 48100433 is 33400184.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30393169 + 17707264 = 5513^2 + 4208^2 .

It is a cyclic number.

It is not a de Polignac number, because 48100433 - 26 = 48100369 is a prime.

It is a super-3 number, since 3×481004333 (a number of 24 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 48100399 and 48100408.

It is not a weakly prime, because it can be changed into another prime (48100483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24050216 + 24050217.

It is an arithmetic number, because the mean of its divisors is an integer number (24050217).

Almost surely, 248100433 is an apocalyptic number.

It is an amenable number.

48100433 is a deficient number, since it is larger than the sum of its proper divisors (1).

48100433 is an equidigital number, since it uses as much as digits as its factorization.

48100433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 48100433 is about 6935.4475702726. The cubic root of 48100433 is about 363.6774126444.

The spelling of 48100433 in words is "forty-eight million, one hundred thousand, four hundred thirty-three".