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48103754011312 = 243006484625707
BaseRepresentation
bin10101111000000000001110…
…01010111001001010110000
320022022200012022210021211111
422330000013022321022300
522301112442011330222
6250150320504523104
713063244603440666
oct1274000712711260
9208280168707744
1048103754011312
111436676209369a
12548a9b5a80494
1320ac21a65310c
14bc433c5b8c36
15586450751777
hex2bc0072b92b0

48103754011312 has 10 divisors (see below), whose sum is σ = 93201023396948. Its totient is φ = 24051877005648.

The previous prime is 48103754011211. The next prime is 48103754011331. The reversal of 48103754011312 is 21311045730184.

It is a super-3 number, since 3×481037540113123 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1503242312838 + ... + 1503242312869.

Almost surely, 248103754011312 is an apocalyptic number.

It is an amenable number.

48103754011312 is a deficient number, since it is larger than the sum of its proper divisors (45097269385636).

48103754011312 is a wasteful number, since it uses less digits than its factorization.

48103754011312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3006484625715 (or 3006484625709 counting only the distinct ones).

The product of its (nonzero) digits is 80640, while the sum is 40.

Adding to 48103754011312 its reverse (21311045730184), we get a palindrome (69414799741496).

The spelling of 48103754011312 in words is "forty-eight trillion, one hundred three billion, seven hundred fifty-four million, eleven thousand, three hundred twelve".

Divisors: 1 2 4 8 16 3006484625707 6012969251414 12025938502828 24051877005656 48103754011312