481333340125111 has 2 divisors, whose sum is σ = 481333340125112. Its totient is φ = 481333340125110.

The previous prime is 481333340125097. The next prime is 481333340125193. The reversal of 481333340125111 is 111521043333184.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 481333340125111 - 2¹¹ = 481333340123063 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (481333340125411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240666670062555 + 240666670062556.

It is an arithmetic number, because the mean of its divisors is an integer number (240666670062556).

Almost surely, 2^{481333340125111} is an apocalyptic number.

481333340125111 is a deficient number, since it is larger than the sum of its proper divisors (1).

481333340125111 is an equidigital number, since it uses as much as digits as its factorization.

481333340125111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 40.

Adding to 481333340125111 its reverse (111521043333184), we get a palindrome (592854383458295).

The spelling of 481333340125111 in words is "four hundred eighty-one trillion, three hundred thirty-three billion, three hundred forty million, one hundred twenty-five thousand, one hundred eleven".