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4819534339129 is a prime number
BaseRepresentation
bin100011000100010001010…
…1000011101110000111001
3122001202001122010200112121
41012020202220131300321
51112430401242323004
614130021415041241
71005125360645146
oct106104250356071
918052048120477
104819534339129
111598a53542494
1265a084370221
1328c631b2b953
141293a3bb33cd
15855791d4854
hex46222a1dc39

4819534339129 has 2 divisors, whose sum is σ = 4819534339130. Its totient is φ = 4819534339128.

The previous prime is 4819534339097. The next prime is 4819534339153. The reversal of 4819534339129 is 9219334359184.

It is a happy number.

4819534339129 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2880324911104 + 1939209428025 = 1697152^2 + 1392555^2 .

It is a cyclic number.

It is not a de Polignac number, because 4819534339129 - 25 = 4819534339097 is a prime.

It is a super-2 number, since 2×48195343391292 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4819538339129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2409767169564 + 2409767169565.

It is an arithmetic number, because the mean of its divisors is an integer number (2409767169565).

Almost surely, 24819534339129 is an apocalyptic number.

It is an amenable number.

4819534339129 is a deficient number, since it is larger than the sum of its proper divisors (1).

4819534339129 is an equidigital number, since it uses as much as digits as its factorization.

4819534339129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25194240, while the sum is 61.

The spelling of 4819534339129 in words is "four trillion, eight hundred nineteen billion, five hundred thirty-four million, three hundred thirty-nine thousand, one hundred twenty-nine".