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48244270284517 is a prime number
BaseRepresentation
bin10101111100000101111101…
…00101111011111011100101
320022211002220010221120021111
422332002332211323323211
522310413231143101032
6250335040052145021
713106350664161666
oct1276027645737345
9208732803846244
1048244270284517
11144103099394aa
1254b2090608171
1320bc5521771c8
14bcb06c5d736d
15589e26952c47
hex2be0be97bee5

48244270284517 has 2 divisors, whose sum is σ = 48244270284518. Its totient is φ = 48244270284516.

The previous prime is 48244270284467. The next prime is 48244270284547. The reversal of 48244270284517 is 71548207244284.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40565613144996 + 7678657139521 = 6369114^2 + 2771039^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48244270284517 is a prime.

It is a super-2 number, since 2×482442702845172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48244270284547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24122135142258 + 24122135142259.

It is an arithmetic number, because the mean of its divisors is an integer number (24122135142259).

Almost surely, 248244270284517 is an apocalyptic number.

It is an amenable number.

48244270284517 is a deficient number, since it is larger than the sum of its proper divisors (1).

48244270284517 is an equidigital number, since it uses as much as digits as its factorization.

48244270284517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32112640, while the sum is 58.

The spelling of 48244270284517 in words is "forty-eight trillion, two hundred forty-four billion, two hundred seventy million, two hundred eighty-four thousand, five hundred seventeen".