Base | Representation |
---|---|
bin | 10101111100101111111101… |
… | …11110101010001011010111 |
3 | 20022220021010001021021210221 |
4 | 22332113332332222023113 |
5 | 22311300424241444303 |
6 | 250353250133255211 |
7 | 13111106633053021 |
oct | 1276277676521327 |
9 | 208807101237727 |
10 | 48266825343703 |
11 | 1441993365828a |
12 | 54b6526194507 |
13 | 20c1707cbb385 |
14 | bcc1abd83011 |
15 | 58a7e6b734bd |
hex | 2be5fefaa2d7 |
48266825343703 has 2 divisors, whose sum is σ = 48266825343704. Its totient is φ = 48266825343702.
The previous prime is 48266825343691. The next prime is 48266825343749. The reversal of 48266825343703 is 30734352866284.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48266825343703 - 217 = 48266825212631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48266825343773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24133412671851 + 24133412671852.
It is an arithmetic number, because the mean of its divisors is an integer number (24133412671852).
Almost surely, 248266825343703 is an apocalyptic number.
48266825343703 is a deficient number, since it is larger than the sum of its proper divisors (1).
48266825343703 is an equidigital number, since it uses as much as digits as its factorization.
48266825343703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139345920, while the sum is 61.
The spelling of 48266825343703 in words is "forty-eight trillion, two hundred sixty-six billion, eight hundred twenty-five million, three hundred forty-three thousand, seven hundred three".
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