Base | Representation |
---|---|
bin | 10101111101111111001111… |
… | …11000100011011010010111 |
3 | 20100001022222021112220000222 |
4 | 22332333213320203122113 |
5 | 22313000111202240434 |
6 | 250425005401024555 |
7 | 13114144441545146 |
oct | 1276774770433227 |
9 | 210038867486028 |
10 | 48309387540119 |
11 | 14435994930422 |
12 | 550282418515b |
13 | 20c572bb38994 |
14 | bd028895175d |
15 | 58b98856e72e |
hex | 2befe7e23697 |
48309387540119 has 2 divisors, whose sum is σ = 48309387540120. Its totient is φ = 48309387540118.
The previous prime is 48309387540097. The next prime is 48309387540133. The reversal of 48309387540119 is 91104578390384.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48309387540119 - 232 = 48305092572823 is a prime.
It is a super-2 number, since 2×483093875401192 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48309387540179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24154693770059 + 24154693770060.
It is an arithmetic number, because the mean of its divisors is an integer number (24154693770060).
Almost surely, 248309387540119 is an apocalyptic number.
48309387540119 is a deficient number, since it is larger than the sum of its proper divisors (1).
48309387540119 is an equidigital number, since it uses as much as digits as its factorization.
48309387540119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26127360, while the sum is 62.
The spelling of 48309387540119 in words is "forty-eight trillion, three hundred nine billion, three hundred eighty-seven million, five hundred forty thousand, one hundred nineteen".
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