Base | Representation |
---|---|
bin | 10101111110000011000011… |
… | …01010010101010001000111 |
3 | 20100001112020122222201220212 |
4 | 22333001201222111101013 |
5 | 22313013302220220034 |
6 | 250425544223350035 |
7 | 13114246200544565 |
oct | 1277014152252107 |
9 | 210045218881825 |
10 | 48311430632519 |
11 | 1443684312aa3a |
12 | 55030b445231b |
13 | 20c59961c02b2 |
14 | bd0400026a35 |
15 | 58ba57ae52ce |
hex | 2bf061a95447 |
48311430632519 has 2 divisors, whose sum is σ = 48311430632520. Its totient is φ = 48311430632518.
The previous prime is 48311430632477. The next prime is 48311430632551. The reversal of 48311430632519 is 91523603411384.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48311430632519 - 220 = 48311429583943 is a prime.
It is a super-2 number, since 2×483114306325192 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48311430632119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24155715316259 + 24155715316260.
It is an arithmetic number, because the mean of its divisors is an integer number (24155715316260).
Almost surely, 248311430632519 is an apocalyptic number.
48311430632519 is a deficient number, since it is larger than the sum of its proper divisors (1).
48311430632519 is an equidigital number, since it uses as much as digits as its factorization.
48311430632519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 50.
The spelling of 48311430632519 in words is "forty-eight trillion, three hundred eleven billion, four hundred thirty million, six hundred thirty-two thousand, five hundred nineteen".
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