Base | Representation |
---|---|
bin | 101100111111110111… |
… | …110011011111100101 |
3 | 11121201020111222111002 |
4 | 230333313303133211 |
5 | 1242422423434301 |
6 | 34110212323045 |
7 | 3330215132051 |
oct | 547767633745 |
9 | 147636458432 |
10 | 48316233701 |
11 | 1954428855a |
12 | 9445013485 |
13 | 472cc884c8 |
14 | 24a4c72c61 |
15 | 13cbb4b16b |
hex | b3fdf37e5 |
48316233701 has 2 divisors, whose sum is σ = 48316233702. Its totient is φ = 48316233700.
The previous prime is 48316233677. The next prime is 48316233709. The reversal of 48316233701 is 10733261384.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36440901025 + 11875332676 = 190895^2 + 108974^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-48316233701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48316233709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24158116850 + 24158116851.
It is an arithmetic number, because the mean of its divisors is an integer number (24158116851).
Almost surely, 248316233701 is an apocalyptic number.
It is an amenable number.
48316233701 is a deficient number, since it is larger than the sum of its proper divisors (1).
48316233701 is an equidigital number, since it uses as much as digits as its factorization.
48316233701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
The spelling of 48316233701 in words is "forty-eight billion, three hundred sixteen million, two hundred thirty-three thousand, seven hundred one".
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